Construct binary tree from inorder and postorder traversal

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Given the inorder and postorder traversals of a binary tree with distinct values, rebuild the tree. The last postorder value is the root; its position in the inorder list splits the left and right subtrees. Write it first with list slicing, then with index bounds and a value-to-index map so it runs in linear time.

NvidiaTechnical phone screenLast asked Aug 2025
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